国产探花免费观看_亚洲丰满少妇自慰呻吟_97日韩有码在线_资源在线日韩欧美_一区二区精品毛片,辰东完美世界有声小说,欢乐颂第一季,yy玄幻小说排行榜完本

首頁 > 學院 > 開發設計 > 正文

PAT A1008. Elevator (20)

2019-11-08 02:03:39
字體:
來源:轉載
供稿:網友

The highest building in our city has only one elevator. A request list is made up with N positive numbers. The numbers denote at which floors the elevator will stop, in specified order. It costs 6 seconds to move the elevator up one floor, and 4 seconds to move down one floor. The elevator will stay for 5 seconds at each stop.

For a given request list, you are to compute the total time spent to fulfill the requests on the list. The elevator is on the 0th floor at the beginning and does not have to return to the ground floor when the requests are fulfilled.

Input Specification:

Each input file contains one test case. Each case contains a positive integer N, followed by N positive numbers. All the numbers in the input are less than 100.

Output Specification:

For each test case, PRint the total time on a single line.

Sample Input:
3 2 3 1Sample Output:
41
#include <cstdio>#include <algorithm>#include <cstring>#include <string>#define Max 100010using namespace std;int main(){	int n,p,q;	int m=0;	scanf("%d",&n);	p=0;	for(int i=0;i<n;i++)	{		scanf("%d",&q);		if(q>p)		{			m+=(q-p)*6;		}		else m+=(p-q)*4;		p=q;		m+=5;	}		printf("%d/n",m);	system("pause");	return 0;}
發表評論 共有條評論
用戶名: 密碼:
驗證碼: 匿名發表
主站蜘蛛池模板: 正阳县| 葵青区| 秭归县| 西宁市| 务川| 关岭| 和静县| 富源县| 河西区| 惠安县| 祁东县| 菏泽市| 澎湖县| 论坛| 千阳县| 江城| 临武县| 通河县| 兴业县| 林口县| 南江县| 交城县| 治县。| 岗巴县| 金秀| 博湖县| 巧家县| 库车县| 河北区| 隆昌县| 汉沽区| 尉氏县| 无锡市| 漳州市| 雷波县| 双城市| 双城市| 和平区| 银川市| 江孜县| 固安县|