用string保存數字
#include<iostream>#include<string>using namespace std;string add(string &a, string &b){ int c = 0;//進位 if (a.size() < b.size()) return add(b, a); a.assign(a.rbegin(), a.rend()); b.assign(b.rbegin(), b.rend()); int low = 0; while (low < b.size()) { int temp = (a[low] + b[low]-'0'-'0' + c) / 10; a[low] = (a[low] + b[low] - '0' - '0' + c) % 10+'0'; c=temp; low++; } while (low < a.size()) { int temp = (a[low]-'0' + c) / 10; a[low] = (a[low] -'0'+c) % 10+'0'; c = temp; low++; } if (c == 1) a.push_back('1'); a.assign(a.rbegin(), a.rend()); return a;}int main(){ string a, b; int N; cin >> N; for (int t = 1;t <= N;t++) { if (t != 1) cout << endl; cin >> a >> b; printf("Case %d:/n%s + %s = ", t, a.c_str(), b.c_str()); cout << add(a, b) << endl; }}新聞熱點
疑難解答
