分析；暴力求解

AC代碼：

#include<cstdio>#include<cstring>using namespace std;int main(){	int n;	while(scanf("%d",&n)==1){		bool fg=0;		for(int i=10000;i<1000000;i++){			int a[6];			int count1=0,sum=0;			int t=i;			while(t){				a[count1]=t%10;				sum+=a[count1++];				t/=10;			}			if(sum==n){			bool flag=0;			for(int j=0;j<=count1/2;j++)			{				if(a[j]!=a[count1-1-j]){					flag=1;					break;				}			}			if(!flag){			PRintf("%d/n",i);			fg=1;     		}		  } 		}		if(!fg)printf("-1/n");	}	return 0;}