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Shell腳本傳參數方法總結

2019-10-26 18:45:59
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一、接收固定長度的參數
代碼如下:
[root@svn shell_example]# cat params.sh
#!/bin/bash
#傳參測試腳本
echo "My name is `basename $0` -I was called as $0"
echo "My first parameter is : $1"
echo "My second parameter is : $2"

空參數執行
代碼如下:
[root@svn shell_example]# sh params.sh
My name is params.sh -I was called as params.sh
My first parameter is :
My second parameter is :

傳遞2個參數執行
代碼如下:
[root@svn shell_example]# sh params.sh one two
My name is params.sh -I was called as params.sh
My first parameter is : one
My second parameter is : two

二、那如果還有參數怎么辦呢?還要一個個加上來嗎?答案是否定的

以下用法應該不陌生,就是直接執行腳本本身,沒有附帶任何參數,那么腳本講拋出幫助信息.即怎么使用此腳本.見紅字部分
代碼如下:
[root@svn shell_example]# sh params_v2.sh
My name is params_v2.sh -I was called as params_v2.sh
I was called with 0 parameters.
Usage: params_v2.sh first second
You provided 0 parameters,but 2 are required.

代碼如下
代碼如下:
[root@svn shell_example]# cat params_v2.sh
#!/bin/bash
# 這是個測試腳本傳參的測試例子

echo "My name is `basename $0` -I was called as $0"
echo "I was called with $# parameters."

if [ "$#" -eq "2" ];then
    echo "My first parameter is $1"
    echo "My second parameter is $2"
else
    echo "Usage: `basename $0` first second"
    echo "You provided $# parameters,but 2 are required."
fi

詳細的執行過程如下
不傳參數執行
代碼如下:
[root@svn shell_example]# sh params_v2.sh
My name is params_v2.sh -I was called as params_v2.sh
I was called with 0 parameters.
Usage: params_v2.sh first second
You provided 0 parameters,but 2 are required.

傳遞3個參數執行
代碼如下:
[root@svn shell_example]# sh params_v2.sh one two three
My name is params_v2.sh -I was called as params_v2.sh
I was called with 3 parameters.
Usage: params_v2.sh first second
You provided 3 parameters,but 2 are required.

傳遞2個參數執行
代碼如下:
[root@svn shell_example]# sh params_v2.sh one two
My name is params_v2.sh -I was called as params_v2.sh
I was called with 2 parameters.
My first parameter is one
My second parameter is two

問題來了,要是后期還要加參數怎么辦呢?或者我也不確定到底會傳幾個參數.
解決方法如下,詳細執行結果如下
代碼如下:
[root@svn shell_example]# cat manyparams.sh
#!/bin/bash
#這是個測試腳本傳N個參數的例子

echo "我的名字是 `basename $0` - 我是調用自 $0"

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