要實現的SQL查詢很原始：

要求從第一個表進行查詢得到第二個表格式的數據，上網查詢之后竟然能寫出下面的SQL：

復制代碼 代碼如下:

select * from userino

SELECT * FROM(
SELECT DISTINCT userpart
FROM userino
)A
OUTER APPLY(
SELECT
[usernames]= replace(replace(replace((SELECT username as value FROM userino N
WHERE userpart = A.userpart order by n.username asc FOR XML AUTO),'"/><N value="','/')
,'<N value="',''),'"/>','')
)N
OUTER APPLY(
SELECT
[username_cns]= replace(replace(replace((SELECT username_cn as value FROM userino M
WHERE userpart = A.userpart order by m.username asc FOR XML AUTO),'"/><M value="','/')
,'<M value="',''),'"/>','')

)M

復制代碼 代碼如下:

select * from
(select * from userino) A
cross join (select username from userino
where username = A.username )B

select * from
(select * from userino) A
join (select username from userino ) B on a.username = b.username

select * from
(select * from userino) A
OUTER APPLY (select username from userino
where username = A.username ) B

復制代碼 代碼如下:

select * from
(select * from userino) A
OUTER APPLY (select [value] = a.username+'test' ) B